Resolved Button open url in safari

hi!

code open url in safari on click:

[[uiapplication sharedapplication] openurl:[nsurl urlwithstring"http://www.apple.com"]];

don't know code should be. tried put in in viewcontroller.m below viewdidunload. can't button work.

i'm new xcode, hope can me.

sorry english.

 

what posted piece of code, need put inside method.

benefit lot reading objective-c

 

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